Sujet : Re: Every sufficiently competent C programmer knows --- posthumous reviewers
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 13. Mar 2025, 21:56:22
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vqvgpn$3s1qt$4@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13
User-Agent : Mozilla Thunderbird
On 3/13/2025 4:22 AM, Mikko wrote:
On 2025-03-13 00:36:04 +0000, olcott said:
>
void DDD()
{
HHH(DDD);
return;
}
>
int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
>
When HHH correctly emulates N steps of the
above functions none of them can possibly reach
their own "return" instruction and terminate normally.
Nevertheless, assuming HHH is a decider, Infinite_Loop and Infinite_Recursion
specify a non-terminating behaviour, DDD specifies a terminating behaviour
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
What is the sequence of machine language
instructions of DDD emulated by HHH such that DDD
reaches its machine address 00002183?
Any failure to answer with the sequence of machine
addresses will be construed as
YOU KNOW THAT YOU ARE LYING OR DON'T UNDERSTAND THE QUESTON
-- Copyright 2025 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer
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