Re: how to make it work

James Kuyper wrote:

fir <fir@grunge.pl> writes:
...

fir <fir@grunge.pl> writes:
>

see such code
>
>
long long unsigned tag ;
>
void foo(long long unsigned tag)
{
   if(tag=='warsaw') printf("\nwarsaw");
   if(tag=='paris')  printf("\nparis");
   if(tag=='new york') printf("\nnew york");
   if(tag=='old york') printf("\nold york");
   if(tag=='very old york') printf("\nvery old york");

...

- my example work on up to 4 lellets/digits/signs
but i dont know how to make it work for 8

>
"An integer character constant has type int. ... The
value of an integer character constant containing more than one
character, ... is implementation-defined."
>
The implementation you're using apparently defines a different value for
each possible combination of 4 characters, which is the maximum number
allowed if sizeof(int)==4. Keep in mind that, since the mapping is
implementation-defined, such code is non-portable. For instance, it's
entirely possible that an implementation sets the value of a
multi-character constant solely by looking at it's first or last
characters. On some implementation, you might have 'new york' == 'k' and
'old york' == 'k'.
>

as even old c has 64 bit unsigned i guess it should work, but dont know how
to make it work

>
So, by "old c" you mean C99? Before C99, no integer type was guaranteed
to have more than 32 bits.
>

very bad but at least clear
hovever as c standard rules/statements or how to call it are
dome to make c have sense then this rule should be changed
to this
An integer character constant mau have any integer type from simple types
avalieble (it is char, short, int long etc) - the value for it is like
adequate string ofd such walue would have in ram say 'lalalala" would heve
walule of 0x6c616c616c616c61