Sujet : Re: 1KV buck converter
De : jl (at) *nospam* glen--canyon.com (john larkin)
Groupes : sci.electronics.designDate : 26. May 2025, 16:48:09
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <h1393khf76cd4vm9tjtqv0d2dqq7rp4o5f@4ax.com>
References : 1 2 3 4 5 6
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On Mon, 26 May 2025 11:00:42 -0400, legg <
legg@nospam.magma.ca> wrote:
On Sun, 25 May 2025 09:35:48 -0700, john larkin <jl@glen--canyon.com>
wrote:
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On Sun, 25 May 2025 10:40:54 -0400, legg <legg@nospam.magma.ca> wrote:
>
On Sat, 24 May 2025 10:35:21 -0700, john larkin <jl@glen--canyon.com>
wrote:
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On Sat, 24 May 2025 12:23:52 -0400, legg <legg@nospam.magma.ca> wrote:
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On Fri, 23 May 2025 08:05:28 -0700, john larkin <jl@glen--canyon.com>
wrote:
>
>
https://www.dropbox.com/scl/fi/f64mv46qk4g4nca00bgoe/1KV_Buck.jpg?rlkey=f0qnaliz7nyoowe6w4wx2gkua&raw=1
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The highest diac rep rate will likely be in the tens of hertz range.
(think cicada)
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RL
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Why? Diacs and sidacs turn on in under a microsecond. I can't imagine
them taking milliseconds to turn off.
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Interestingly, sidacs have been used in series strings up to many
kilovolts, which suggets a kilovolt step-down converter with
diacs/sidacs as the only active components.
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>
Punch some numbers.
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Numbers are cheap. 2 nF charged to 1 KV stores a millijoule. Transfer
that at 10 Hz and you get the required 10 mW.
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The problem is the circuit.
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Diac section is pretty simple to breadboard.
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RL
I needs a circuit first.
One could charge an RC and use diacs to dump that into an inductor,
basically make a pulse-driven buck regulator. But charging the
capacitor would be inefficient. I'd expect overall efficiency to be
maybe 25%.