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On 3/31/24 20:15, Jim Pennino wrote:In sci.physics Physfitfreak <physfitfreak@gmail.com> wrote:
<snip old crap and random babble>
If the missile computes that 5 fighter jets at time t will exactly be at
these coordinates in the sky:
>
Jet 1: (4.38 km, 3.9 km, 8.1 km)
Jet 2: (5.23 km, 9.61 km, 4.74 km)
Jet 3: (6.93 km, 6.01 km, 6.88 km)
Jet 4: (8.32 km, 2.12 km, 2.5 km)
Jet 5: (2.53 km, 4.23 km, 5.82 km)
>
then answer the following 2 questions:
>
1- what would be the coordinates of the point in the sky, that the
missile with the weakest warhead needs to explode at, at time t, to
damage all those 5 fighter jets critically enough?
It depends on the velocity, which in physics has both a direction and
magnitude, of the jets.
>
2- within what minimum radius of that explosion, any fighter jet would
get critically damaged at time t?
>
And again, it depends on the velocity, which in physics has both a
direction and magnitude, of the jets.
Jets have long been able to outrun an explosion, even nuclear given
enough lead, that is behind them.
You also need to know the characteristics of the warhead, which is
measured in overpressure versus distance from detonation.
Not that you've got any intention to solve the problem (I don't think
you can solve it) and you just want to be a dick as usual, still, I add
for others who may be interested, that the point you're making is the
business of missile's own software, and not this problem. Missile itself
computes the point at which it can get just early enough and explode so
the damaging effects would reach all five targets by the time t and at
those five locations that the targets are, as given above.
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