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On Sun, 12 May 2024 13:46:28 -0000 (UTC), Thomas Koenig
<tkoenig@netcologne.de> wrote:John Savard <quadibloc@servername.invalid> schrieb:
>I have instead defined a 256-bit format for floats which does not have>
a hidden first bit, which looks like the old temporary reals, except
that the exponent field is one bit wider.
Why not the IEEE binary256 (interchange) format?
>
https://en.wikipedia.org/wiki/Octuple-precision_floating-point_format
Oh, drat. I had not realized that they had also defined this.
Now that means I need to make the exponent field in my internal
format larger, define a 512-bit floating point number which is in the
internal format, so that it can be unnormalized, and a 1024-bit
doubled-up float... instead of what I just did!
The enlarged exponent field won't make the internal form of the
128-bit float go over 160 bits, so register allocation for th at won't
change... but now I will have to figure out a scheme of register
allocation applicable to the 256-bit floats!
I am not amused.Question:: why are you all so gung-ho on having a format without a hidden bit.
John Savard
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