Re: Faster div or 1/sqrt approximations

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Sujet : Re: Faster div or 1/sqrt approximations
De : anton (at) *nospam* mips.complang.tuwien.ac.at (Anton Ertl)
Groupes : comp.arch
Date : 21. Jul 2024, 14:11:56
Autres entêtes
Organisation : Institut fuer Computersprachen, Technische Universitaet Wien
Message-ID : <2024Jul21.151156@mips.complang.tuwien.ac.at>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13
User-Agent : xrn 10.11
Thomas Koenig <tkoenig@netcologne.de> writes:
Terje Mathisen <terje.mathisen@tmsw.no> schrieb:
However, if you are willing to take that first NR iteration
>
  halfnumber = 0.5f*x
  ...
  i = R-(i>>1);
  ...
  x = x*(1.5f-halfnumber*x*x);
>
and then make both the 0.5f and 1.5f constants free variables, you can
in fact get 1.5 more bits than what they show in this paper.
...
Looks like https://web.archive.org/web/20180709021629/http://rrrola.wz.cz/inv_sqrt.html
who reports 6.50196699E−4 as the maximum error (also from the
Wikipedia article).
>
That's 10.5 bits of accuracy, not bad at all.
>
However... assume you want to do another NR step.  In that case,
you might be better off not loading different constants from memory,
so having the same constants might actually be an advantage
(whch does not mean that they have to be the original Newton steps).

The number of accurate digits doubles after each NR step, so starting
with the better first "NR" iteration would result in an additional
accuracy of 3 bits.  And if you optimize the new constants for the
second iteration, you may even get more.  Or you could optimize for
two iterations using the same constants ...

- anton
--
'Anyone trying for "industrial quality" ISA should avoid undefined behavior.'
  Mitch Alsup, <c17fcd89-f024-40e7-a594-88a85ac10d20o@googlegroups.com>

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