Sujet : Re: [ANN] GCC 14.2.0-3 (aarch64, macOS)
De : Keith.S.Thompson+u (at) *nospam* gmail.com (Keith Thompson)
Groupes : comp.lang.adaDate : 30. Nov 2024, 22:15:24
Autres entêtes
Organisation : None to speak of
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Keith Thompson <Keith.S.Thompson+
u@gmail.com> writes:
Simon Wright <simon@pushface.org> writes:
Björn Persson <Bjorn@rombobjörn.se> writes:
It happened today in GCC 14.2.1 (as packaged in Fedora 41), so no, not
only in 14.2.0.
>
There's no official FSF 14.2.1 release - it may just be like Alire,
which only handles 3 levels, so they call the first packaging of 14.2.0
14.2.1. If you say 'gcc -v' it'll probably say 14.2.0.
>
Of course I could be completely wrong and Fedora have added lots of
value!
>
I see some potential for confusion, since there almost certainly will be
an official gcc 14.2.1 release in the near future. That official
release will include code that's not included in what Fedora calls gcc
14.2.1. It's a point release, so I wouldn't expect substantial changes,
but still, I think Fedora should use a different naming scheme.
After I wrote the above, I built gcc from its git repo, using the tip
of the releases/gcc-14 branch (not a release tag). Presumably the
Fedora folks did something similar. The resulting gcc reports its
own version as :
$ gcc --version
gcc (GCC) 14.2.1 20241129
whereas a gcc built from the releases/gcc-14.2.0 tag reports :
$ gcc --version
gcc (GCC) 14.2.0
with no date.
I still see some potential for confusion, but not as much as I initially
thought. (The fact that gcc doesn't do *.*.1 releases is fairly
obscure, and I wouldn't expect most people to know about it.)
-- Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.comvoid Void(void) { Void(); } /* The recursive call of the void */