Re: printing words without newlines?

<snip>
I'm learning more AWK basics and wrote function to read file, sort,
print.  I use GNU AWK (gawk) and its sort but printing is harder to get
working than anything... separate lines work, but when I use printf() or
set ORS then use print (for words one line) all awk outputs (on FreeBSD
UNIX 14 and Slackware GNU/Linux 15) is a space (and not even newline
before shell prompt)... is this normal (and I made mistake?) or am I
approaching it wrong?  I recall BASIC prints new lines, but as I learned
basic C and some derivatives, I'm used to newlines only being specified...
------------------------------------------------------------------------
# print_file_words.awk
# pass filename to function
BEGIN { print_file_words("data.txt"); }
>
# read two-column array from file and sort lines and print
function print_file_words(file) {
# set record separator then use print
# ORS=" "
 while(getline<file) arr[$1]=$0
 PROCINFO["sorted_in"]="@ind_num_asc"
 for(i in arr)
 {
   split(arr[i],arr2)
   # output all words or on one line with ORS
   print arr2[2]
   # output all words on one line without needing ORS
   #printf("%s ",arr2[2])
 }
}
<snip>

I think you forgot that arr2 is now an array => you have to iterate over
it as well.  There were also a few other coding errors, ie. not closing
the data.txt file; not declaring local vars in print_file_words:

--
$ cat test.awk
BEGIN { print_file_words("data.txt") }

function print_file_words(file,  i,j) {
  ORS = " "
  PROCINFO["sorted_in"]="@ind_num_asc"
  while (getline <file >0)
    arr[$1] = $0
  close (file)

  for(i in arr) {
    split(arr[i],arr2)
for (j in arr2)
      print arr2[j]
  }
  ORS = "\n"
  print ""
}

$ gawk -f test.awk
all are base belong to us your
--

Probably this is not the best way of doing things but I think you're
mainly just experimenting with sorting/printing so..