Re: Operator precedence

Kaz Kylheku <643-408-1753@kylheku.com> writes:

in the left associative semantics, we have a choice. We can do the
exponentation earnestly as if by:
>
  (expt (expt 5 2) 3)
>
Or we can take advantage of the identity:
>
  (expt 5 (* 2 3))
>
The former could be important in some situation involving
floating-point: you can't always use simplifying identities.

I cannot readily imagine a scenario in which simplifying is not possible
or is disadvantageous. Could you please elaborate?

I felt that the n-ary semantics of expt provided the best value
when right associative. It's not something obtainable by a ready
identity, and there is one obvious way to do it.

Full ACK.

Best regards

Axel