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On 6/28/2025 11:22 AM, Mike Terry wrote:ok I see you intend to be completely non-responsive, just as you were in the "diverging simulations" thread.On 28/06/2025 16:00, olcott wrote:Do you know what a number is?On 6/27/2025 7:14 PM, Mike Terry wrote:>On 27/06/2025 20:36, olcott wrote:>I am only here for the validation of the behavior>
of DDD correctly simulated by HHH.
>
I have included proof that the people on comp.theory
lied about this at the bottom.
>
typedef void (*ptr)();
int HHH(ptr P);
>
void DDD()
{
HHH(DDD);
return;
}
>
int main()
{
HHH(DDD);
DDD();
}
>
Termination Analyzer HHH simulates its input until
it detects a non-terminating behavior pattern. When
HHH detects such a pattern it aborts its simulation
and returns 0.
>
On 6/27/2025 12:27 PM, Alan Mackenzie wrote:
> In comp.theory olcott <polcott333@gmail.com
> wrote:
>
>> I know that DDD .... simulated by HHH cannot
>> possibly reach its own simulated "return" statement
>> final halt state because the execution trace
>> conclusively proves this.
>
> Everybody else knows this, too, and nobody has
> said otherwise. *The conclusion is that the*
> *simulation by HHH is incorrect*
>
>
*That last sentence is an intentional falsehood*
Well, people here use the term "simulation" in a number of ways, right?
*There is only one correct way*
That's patently rubbish.
>
This is one of your major cognitive mistakes - believing that the squiggles which make up words have an absolute meaning independently of the people using them to (hopefully) communicate.
>>>
void DDD()
{
HHH(DDD);
return;
}
>
The correct simulation of DDD by HHH means that HHH simulates
DDD and then emulates itself simulating DDD a number of times
according to the semantics of C.
"a number of times"???
>
In this case I am referring to every non-negative integer.
a) Does a correct simulation need to simulate until its target computation terminates?There is no target computation here we only have the
>
behavior that the input to HHH(DDD) specifies.
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