Sujet : Re: 'Graphics' of libwy
De : Keith.S.Thompson+u (at) *nospam* gmail.com (Keith Thompson)
Groupes : comp.lang.c++Date : 20. Dec 2024, 02:07:09
Autres entêtes
Organisation : None to speak of
Message-ID : <87wmfvw4aq.fsf@nosuchdomain.example.com>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14
User-Agent : Gnus/5.13 (Gnus v5.13)
Ross Finlayson <
ross.a.finlayson@gmail.com> writes:
On 12/18/2024 08:14 PM, Keith Thompson wrote:
wij <wyniijj5@gmail.com> writes:
On Wed, 2024-12-18 at 18:29 -0800, Keith Thompson wrote:
wij <wyniijj5@gmail.com> writes:
On Wed, 2024-12-18 at 13:12 -0800, Keith Thompson wrote:
[...]
I think now the answer may lie at what the cout (terminal) is.
E.g. gnome-terminal --geometry=200x100 --zoom=0.5 -- ./a.out
a.out is now plotting on a 200x100 drawing board.
>
C++ can provide a graphics library, but not necessarily a GUI library.
>
That's a text terminal. Sure, you can do "graphics" in text mode, but I
don't think that's what anyone has been talking about.
>
But, what is the true thing the program is dealing with? What is 'pixel'?
>
Do you really not know what a pixel is?
>
I think it is possible to handle and display a photo using 'cout'
>
Possible? Sure.
Desirable? Rarely.
Worth standardizing in the C++ standard? Nope.
>
[...]
>
Pixel = "picture element"
You do know what a pixel is. So why did you ask?
[Long list of definitions of terms deleted]
I don't know what point you're trying to make.
-- Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.comvoid Void(void) { Void(); } /* The recursive call of the void */