Re: counting_semaphore question

On Fri, 13 Sep 2024 15:29:37 +0200
Bonita Montero <Bonita.Montero@gmail.com> boringly babbled:

Am 13.09.2024 um 15:21 schrieb Muttley@dastardlyhq.com:
>

Oh right, so for 32 bit TCP seq number instead of just doing:
 
++tcp->seq_num;
 
which would autonatically wrap after 2^32, in your world we'd have do to:
 
tcp->seq_num = (uint32_t)(((uint_64_t)tcp->seq_num + 1) % 0x100000000L);
 
Really?
 
Don't be an ass.

>
I've also not seen any meaningful code which shows what this
maximum is good for .... But what sense should a wrap-around
make with a semaphore ??? A semaphore should remember all its
releases if possible.

Its not about semaphores any more, its about wrapping values in general.