Sujet : Re: DDD simulated by HHH cannot possibly halt (Halting Problem)
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 05. Apr 2025, 17:45:28
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vsrmn8$2o2f2$1@dont-email.me>
References : 1 2 3 4
User-Agent : Mozilla Thunderbird
On 4/5/2025 2:05 AM, Mikko wrote:
On 2025-04-05 06:18:06 +0000, olcott said:
On 4/4/2025 3:12 AM, Mikko wrote:
On 2025-04-04 01:27:15 +0000, olcott said:
>
void DDD()
{
HHH(DDD);
return;
}
>
Do you really think that anyone knowing the C
programming language is too stupid to see that
DDD simulated by HHH cannot possibly return?
>
Anyone knowing the C language can see that if DDD() does not halt
it means that HHH(DDD) does not halt. The knowledge that that
means that HHH is not a decider is possible but not required.
>
>
*Perpetually ignoring this is not any actual rebuttal at all*
>
*Simulating termination analyzer Principle*
It is always correct for any simulating termination
analyzer to stop simulating and reject any input that
would otherwise prevent its own termination. The
only rebuttal to this is rejecting the notion that
deciders must always halt.
Wrong, because a termination analyzer is not required to halt.
Why say things that you know are untrue?
A termination analyzer that doesn't halt
would flunk every proof of total program correctness.
-- Copyright 2025 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer
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