Sujet : Re: Formal systems that cannot possibly be incomplete except for unknowns and unknowable
De : dbush.mobile (at) *nospam* gmail.com (dbush)
Groupes : comp.theoryDate : 07. May 2025, 22:47:19
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vvgkd7$15i5e$23@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
User-Agent : Mozilla Thunderbird
On 5/7/2025 5:46 PM, olcott wrote:
On 5/7/2025 4:30 PM, Richard Heathfield wrote:
On 07/05/2025 20:35, olcott wrote:
On 5/7/2025 1:59 PM, Richard Heathfield wrote:
On 07/05/2025 19:31, olcott wrote:
>
<snip>
>
>
I already know that the contradictory part of the
counter-example input has always been unreachable code.
>
If the code is unreachable, it can't be part of a working program, so simply remove it.
>
It is unreachable by the Halting Problem counter-example
input D when correctly simulated by the simulating
termination analyzer H that it has been defined to thwart.
>
If the simulation can't reach code that the directly executed program reaches, then it's not a faithful simulation.
>
If is was true that it is not a faithful simulation
then you would be able to show exactly what sequence
of instructions would be a faithful simulation.
The sequence executed by HHH1, as you are on record as admitting is correct:
On 5/6/2025 5:17 PM, dbush wrote:
> On 5/6/2025 5:03 PM, olcott wrote:
>> On 5/6/2025 3:51 PM, dbush wrote:
>>> On 5/6/2025 4:46 PM, olcott wrote:
>>>> On 5/6/2025 3:31 PM, dbush wrote:
>>>>> Then what is the first instruction emulated by HHH that differs
>>>>> from the emulation performed by UTM?
>>>>>
>>>>
>>>> HHH1 is exactly the same as HHH except that DD
>>>> does not call HHH1. This IS the UTM emulator.
>>>> It does not abort.
>>>
>>> Last chance:
>>>
>>> What is the first instruction emulated by HHH that differs from the
>>> emulation performed by HHH1?
>>
>> Go back and read the part you ignored moron.
>
> Let the record show that Peter Olcott has neglected to identify an
> instruction that HHH emulates differently from HHH1.
>
>>> Failure to provide this in your next message or within one hour of
>>> your next post in this newsgroup will be taken as your official on-
>>> the-record admission that the emulations performed by HHH and HHH1
>>> are in fact exactly the same up until the point that HHH aborts, at
>>> which point HHH did not correctly simulate the last instruction it
>>> simulated as you are previously on record as admitting.
>
> Therefore, as per the above requirements:
>
> LET THE RECORD SHOW
>
> That Peter Olcott
>
> Has *officially* admitted
>
> That the emulations performed by HHH and HHH1 are in fact exactly the
> same up until the point that HHH aborts, at which point HHH did not
> correctly simulate the last instruction it simulated as he is previously
> on record as admitting.