Sujet : Re: Formal systems that cannot possibly be incomplete except for unknowns and unknowable
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 08. May 2025, 00:05:07
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vvgov4$1a47o$2@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
User-Agent : Mozilla Thunderbird
On 5/7/2025 5:05 PM, dbush wrote:
On 5/7/2025 5:56 PM, olcott wrote:
On 5/7/2025 4:47 PM, dbush wrote:
On 5/7/2025 5:46 PM, olcott wrote:
On 5/7/2025 4:30 PM, Richard Heathfield wrote:
On 07/05/2025 20:35, olcott wrote:
On 5/7/2025 1:59 PM, Richard Heathfield wrote:
On 07/05/2025 19:31, olcott wrote:
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<snip>
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I already know that the contradictory part of the
counter-example input has always been unreachable code.
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If the code is unreachable, it can't be part of a working program, so simply remove it.
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It is unreachable by the Halting Problem counter-example
input D when correctly simulated by the simulating
termination analyzer H that it has been defined to thwart.
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If the simulation can't reach code that the directly executed program reaches, then it's not a faithful simulation.
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If is was true that it is not a faithful simulation
then you would be able to show exactly what sequence
of instructions would be a faithful simulation.
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The sequence executed by HHH1, as you are on record as admitting is correct:
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What exact sequence of the following machine addresses
of DD emulated by HHH
Which it does incorrectly as you have admitted on the record:
Liar
Yet you cannot show how to do it correctly
because you know that you are lying about it doing
it incorrectly or you are clueless about these things.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer