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On 11/07/2024 00:01, Ben Bacarisse wrote:bart <bc@freeuk.com> writes:
On 10/07/2024 14:32, Ben Bacarisse wrote:I still consider arrays in C to be 'passed' by a
mechanism which is near-indistinguishable from actual
pass-by-reference.
I don't really care how you consider it, but I do care about how you
misrepresent the facts in public.
In another post you said that your language has pass by reference,
and we also know you have implemented C. Either you are just very
confused and your language simply has call by value (after all, you
think C has pass by reference), or you know that pass by reference
in your language needs something from the implementation that was
not needed when you implemented C. I can't decide if you are
confused or just lying.
The way it works in my language is very simple (this is what I do
after all):
type T = int
proc F(T x)= # Pass by value
println x.typestr
end
proc G(ref T x)= # Manual pass-by-reference
println x^.typestr
end
proc H(T &x)= # Auto pass-by-reference
println x.typestr
end
proc main=
T a
F(a)
G(&a)
H(a)
end
I've written 3 functions using pass-by-value, pass-by-value emulating
pass-by-reference, and actual pass-by-reference.
The G function and the call to G show what the compiler has to add
when it processes function H: address-of ops and derefs. The cost is
a single & in the parameter list to get that convenience.
This programs works just the same if T was changed to an array:
type T = [4]int
(The output is 3 lots of '[4]i64' instead of 3 lots of 'i64'; 'int'
is an alias for int64/i64.)
This is regular and orthogonal, a complete contrast to C even though
both languages supposedly operate at the same level.
The behaviour of F, when written in C, is like my F function when T
is an int (obviously the C won't have '.typestr').
But when T is an array, its behaviour is more like that of my H
function.
So, my remark about arrays in C being passed by reference is
understandable.
>
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