Re: technology discussion → does the world need a "new" C ?

On 16/08/2024 02:08, Ben Bacarisse wrote:

Bart <bc@freeuk.com> writes:
 

>
In general there is no reason, in a language with true call-by-reference,
why any parameter type T (which has the form U*, a pointer to anything),
cannot be passed by reference. It doesn't matter whether U is an array type
or not.

 I can't unravel this.  Take, as a concrete example, C++.  You can't pass
a pointer to function that takes an array passed by reference.  You can,
of course, pass a pointer by reference, but that is neither here nor
there.
 

In C++, you can't pass arrays as parameters at all - the language inherited C's handling of arrays.  You can, of course, pass objects of std::array<> type by value or by reference, just like any other class types.