Re: DD simulated by HHH cannot possibly halt (Halting Problem)

On 4/5/2025 8:40 PM, olcott wrote:

On 4/5/2025 6:35 PM, Richard Heathfield wrote:

On 06/04/2025 00:16, olcott wrote:

I am trying to explain how the actual HHH works
one step at a time.

>
But it doesn't, so you're wasting your time. The best you'll manage is to determine the termination status of /some/ programs. That's not in dispute. But all programs? Can't be done, as has been explained to you ad nauseam.
>

 int DD()
{
   int Halt_Status = HHH(DD);
   if (Halt_Status)
     HERE: goto HERE;
   return Halt_Status;
}
 As long as HHH determines the correct halt status
of DD

Which according the the halting function:
Given any algorithm (i.e. a fixed immutable sequence of instructions) X described as <X> with input Y:
A solution to the halting problem is an algorithm H that computes the following mapping:
(<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed directly
Is HALTING, which HHH does not do.