Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory

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Sujet : Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.lang.c comp.lang.c++
Date : 28. Jun 2025, 16:00:52
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <103p034$tj08$1@dont-email.me>
References : 1 2
User-Agent : Mozilla Thunderbird
On 6/27/2025 7:14 PM, Mike Terry wrote:
On 27/06/2025 20:36, olcott wrote:
I am only here for the validation of the behavior
of DDD correctly simulated by HHH.
>
I have included proof that the people on comp.theory
lied about this at the bottom.
>
typedef void (*ptr)();
int HHH(ptr P);
>
void DDD()
{
   HHH(DDD);
   return;
}
>
int main()
{
   HHH(DDD);
   DDD();
}
>
Termination Analyzer HHH simulates its input until
it detects a non-terminating behavior pattern. When
HHH detects such a pattern it aborts its simulation
and returns 0.
>
On 6/27/2025 12:27 PM, Alan Mackenzie wrote:
 > In comp.theory olcott <polcott333@gmail.com
 > wrote:
 >
 >> I know that DDD .... simulated by HHH cannot
 >> possibly reach its own simulated "return" statement
 >> final halt state because the execution trace
 >> conclusively proves this.
 >
 > Everybody else knows this, too, and nobody has
 > said otherwise. *The conclusion is that the*
 > *simulation by HHH is incorrect*
 >
>
*That last sentence is an intentional falsehood*
 Well, people here use the term "simulation" in a number of ways, right? 
*There is only one correct way*
void DDD()
{
   HHH(DDD);
   return;
}
The correct simulation of DDD by HHH means that HHH simulates
DDD and then emulates itself simulating DDD a number of times
according to the semantics of C.
Everyone here knows that DDD correctly simulated by HHH
cannot possibly reach its own simulated "return" statement.
Most everyone on comp.theory lies about this.

Like I've pointed out to you on several occasions.  Maybe you should consider a simple misunderstanding over terminology before assuming bad intentions.
 
After three years on this same point a simple misunderstanding
has been ruled out.

So what does Alan mean by "the simulation by HHH is incorrect", exactly?  (And why do you think it is incorrect?)
 
He is simply lying. Most of the reviews of my work are
counter-factual dogmatic assertions utterly bereft of
any supporting reasoning.

That is a question for PO, rather than Alan, since it is PO who claims Alan is lying...
 Mike.
 
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Date Sujet#  Auteur
27 Jun 25 * DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory10olcott
28 Jun 25 `* Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory9Mike Terry
28 Jun 25  +* Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory6olcott
28 Jun 25  i`* Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory5Mike Terry
28 Jun 25  i `* Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory4olcott
28 Jun 25  i  `* Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory3Mike Terry
28 Jun 25  i   +- Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory1olcott
28 Jun 25  i   `- Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory1olcott
29 Jun 25  +- Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- Liars on comp.theory1olcott
29 Jun 25  `- Re: DDD correctly simulated by HHH can't possibly reach its own "return" statement --- (Typo corrected)1olcott

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