[...]
In C, an expression statement "expr;" causes the expression to be[...]
evaluated as a void expression for its side effects (§6.8.4p2). You
can, arguably, say that C also requires all statements to be of "void"
type, just like Pascal - but the cast-to-void is done implicitly to
treat "expr;" as "(void) expr;".
In an expression statement, the expression is "evaluated as a void
expression for its side effects". I think that's equivalent to
convert (not casting!) it to void, but the standard doesn't describe
it that way.
6.3.2.2: "If an expression of any other type [other than void]
is evaluated as a void expression, its value or designator is
discarded."
But statements have no type.
--
Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.com
void Void(void) { Void(); } /* The recursive call of the void */
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