Re: relearning C: why does an in-place change to a char* segfault?

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Sujet : Re: relearning C: why does an in-place change to a char* segfault?
De : tr.17687 (at) *nospam* z991.linuxsc.com (Tim Rentsch)
Groupes : comp.lang.c
Date : 14. Aug 2024, 02:40:24
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <86h6boszrb.fsf@linuxsc.com>
References : 1 2 3 4 5 6
User-Agent : Gnus/5.11 (Gnus v5.11) Emacs/22.4 (gnu/linux)
Vir Campestris <vir.campestris@invalid.invalid> writes:

On 12/08/2024 22:11, Tim Rentsch wrote:
>
Keith Thompson <Keith.S.Thompson+u@gmail.com> writes:
>
[...]
>
A string literal creates an array object with static storage
duration.  [...]
>
A small quibble.  Every string literal does sit in an array,
but it might not be a _new_ array, because different string
literals are allowed to overlap as long as the bytes in the
overlapping arrays have the right values.
>
And this is exactly why string literals should always have been
const.

The people who wrote the C standard reached a different
conclusion, and IMO the right one.

A compiler is entitled to share memory between strings.  so
>
    puts("lap");
    puts("overlap");
>
it's entitled to make them overlap.  Then add
>
    char * p = "lap";
    *p='X';
>
and it can overwrite the shared string.  I think.  which would
mean that writing "lap" again would have a different result.

A C implementation is also allowed to put every string literal
in its own separate array object, not shared even when two
or more string literals are identical, and make them writable
so they can be modified without problems.  I believe some C
compilers actually did this, perhaps under the control of a
compilation option.

But that ship has sailed.  I'm not even sure const had been
invented that far back!

C was already well established before 'const' was invented, and it
was a number of years after that before some C compilers started
allowing 'const' in source code.  The cost of not being backward
compatible would be high;  the cost adding const incrementally in
new code is low.  Generally speaking using string literals in open
code is a bad idea anyway, regardless whether there is any concern
that the string might be modified.  I think most people who want
string literals to be of type const char[] are only thinking about
one side of the equation.  It's always important to remember to
look at both sides of the cost/benefit forces, and not focus on
just the (imagined) benefits or (imagined) downsides.

Date Sujet#  Auteur
1 Aug 24 * relearning C: why does an in-place change to a char* segfault?98Mark Summerfield
1 Aug 24 +* Re: relearning C: why does an in-place change to a char* segfault?2Mark Summerfield
1 Aug 24 i`- Re: relearning C: why does an in-place change to a char* segfault?1Ben Bacarisse
1 Aug 24 +* Re: relearning C: why does an in-place change to a char* segfault?33Richard Harnden
1 Aug 24 i+- Re: relearning C: why does an in-place change to a char* segfault?1Mark Summerfield
1 Aug 24 i`* Re: relearning C: why does an in-place change to a char* segfault?31Bart
1 Aug 24 i `* Re: relearning C: why does an in-place change to a char* segfault?30Keith Thompson
1 Aug 24 i  +* Re: relearning C: why does an in-place change to a char* segfault?20Bart
1 Aug 24 i  i+- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
2 Aug 24 i  i+- Re: relearning C: why does an in-place change to a char* segfault?1James Kuyper
2 Aug 24 i  i+* Re: relearning C: why does an in-place change to a char* segfault?16Kaz Kylheku
2 Aug 24 i  ii`* Re: relearning C: why does an in-place change to a char* segfault?15Bart
2 Aug 24 i  ii +- Re: relearning C: why does an in-place change to a char* segfault?1Richard Damon
2 Aug 24 i  ii `* Re: relearning C: why does an in-place change to a char* segfault?13James Kuyper
2 Aug 24 i  ii  +- Re: relearning C: why does an in-place change to a char* segfault?1Bart
3 Aug 24 i  ii  +* Re: relearning C: why does an in-place change to a char* segfault?5Lawrence D'Oliveiro
3 Aug 24 i  ii  i`* Re: relearning C: why does an in-place change to a char* segfault?4Richard Damon
3 Aug 24 i  ii  i +- Re: relearning C: why does an in-place change to a char* segfault?1Joe Pfeiffer
4 Aug 24 i  ii  i +- Re: relearning C: why does an in-place change to a char* segfault?1Lawrence D'Oliveiro
12 Aug 24 i  ii  i `- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
14 Aug 24 i  ii  `* Re: relearning C: why does an in-place change to a char* segfault?6Tim Rentsch
14 Aug 24 i  ii   +* Re: relearning C: why does an in-place change to a char* segfault?3Keith Thompson
16 Aug 24 i  ii   i`* Re: relearning C: why does an in-place change to a char* segfault?2Tim Rentsch
16 Aug 24 i  ii   i `- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
14 Aug 24 i  ii   `* Re: relearning C: why does an in-place change to a char* segfault?2James Kuyper
16 Aug 24 i  ii    `- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
4 Aug 24 i  i`- Re: relearning C: why does an in-place change to a char* segfault?1Bonita Montero
12 Aug 24 i  `* Re: relearning C: why does an in-place change to a char* segfault?9Tim Rentsch
13 Aug 24 i   `* Re: relearning C: why does an in-place change to a char* segfault?8Vir Campestris
13 Aug 24 i    +* Re: relearning C: why does an in-place change to a char* segfault?3Keith Thompson
14 Aug 24 i    i+- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
14 Aug 24 i    i`- Re: relearning C: why does an in-place change to a char* segfault?1David Brown
14 Aug 24 i    `* Re: relearning C: why does an in-place change to a char* segfault?4Tim Rentsch
14 Aug 24 i     `* Re: relearning C: why does an in-place change to a char* segfault?3Keith Thompson
14 Aug 24 i      `* Re: relearning C: why does an in-place change to a char* segfault?2Kaz Kylheku
14 Aug 24 i       `- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
1 Aug 24 +* No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?38Michael S
1 Aug 24 i`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?37David Brown
2 Aug 24 i `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?36candycanearter07
2 Aug 24 i  +* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?34Keith Thompson
2 Aug 24 i  i+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?28Richard Harnden
2 Aug 24 i  ii+- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1James Kuyper
2 Aug 24 i  ii+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?24Keith Thompson
2 Aug 24 i  iii+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?5Richard Damon
2 Aug 24 i  iiii+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?3James Kuyper
2 Aug 24 i  iiiii`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2Richard Damon
12 Aug 24 i  iiiii `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
12 Aug 24 i  iiii`- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
2 Aug 24 i  iii+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?15Chris M. Thomasson
3 Aug 24 i  iiii`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?14Ben Bacarisse
3 Aug 24 i  iiii `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?13Chris M. Thomasson
5 Aug 24 i  iiii  `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?12Ben Bacarisse
5 Aug 24 i  iiii   `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?11Chris M. Thomasson
5 Aug 24 i  iiii    +- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Chris M. Thomasson
5 Aug 24 i  iiii    `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?9Ben Bacarisse
5 Aug 24 i  iiii     `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?8Chris M. Thomasson
5 Aug 24 i  iiii      `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?7Ben Bacarisse
6 Aug 24 i  iiii       +* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?5Chris M. Thomasson
6 Aug 24 i  iiii       i`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?4Ben Bacarisse
6 Aug 24 i  iiii       i `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?3Chris M. Thomasson
7 Aug 24 i  iiii       i  `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2Ben Bacarisse
13 Aug 24 i  iiii       i   `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Chris M. Thomasson
6 Aug 24 i  iiii       `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Chris M. Thomasson
12 Aug 24 i  iii`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?3Tim Rentsch
12 Aug 24 i  iii `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2Keith Thompson
3 Sep 24 i  iii  `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
25 Aug 24 i  ii`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2dave thompson 2
25 Aug 24 i  ii `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
12 Aug 24 i  i`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?5Tim Rentsch
12 Aug 24 i  i `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?4Keith Thompson
13 Aug 24 i  i  `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?3Tim Rentsch
13 Aug 24 i  i   `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2David Brown
13 Aug 24 i  i    `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
3 Aug 24 i  `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1David Brown
1 Aug 24 +- Re: relearning C: why does an in-place change to a char* segfault?1James Kuyper
1 Aug 24 `* Re: relearning C: why does an in-place change to a char* segfault?23Kaz Kylheku
1 Aug 24  +* Re: relearning C: why does an in-place change to a char* segfault?20Bart
1 Aug 24  i+- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
1 Aug 24  i+- Re: relearning C: why does an in-place change to a char* segfault?1Ben Bacarisse
2 Aug 24  i+* Re: relearning C: why does an in-place change to a char* segfault?3Kaz Kylheku
2 Aug 24  ii+- Re: relearning C: why does an in-place change to a char* segfault?1Bart
12 Aug 24  ii`- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
3 Aug 24  i`* Re: relearning C: why does an in-place change to a char* segfault?14David Brown
4 Aug 24  i +* Re: relearning C: why does an in-place change to a char* segfault?12Keith Thompson
4 Aug 24  i i+* Re: relearning C: why does an in-place change to a char* segfault?10Lawrence D'Oliveiro
4 Aug 24  i ii`* Re: relearning C: why does an in-place change to a char* segfault?9Keith Thompson
4 Aug 24  i ii +* Re: relearning C: why does an in-place change to a char* segfault?2Richard Damon
12 Aug 24  i ii i`- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
5 Aug 24  i ii `* Re: relearning C: why does an in-place change to a char* segfault?6Lawrence D'Oliveiro
5 Aug 24  i ii  `* Re: relearning C: why does an in-place change to a char* segfault?5Keith Thompson
5 Aug 24  i ii   `* Re: relearning C: why does an in-place change to a char* segfault?4Lawrence D'Oliveiro
6 Aug 24  i ii    `* Re: relearning C: why does an in-place change to a char* segfault?3Keith Thompson
6 Aug 24  i ii     `* Re: relearning C: why does an in-place change to a char* segfault?2Bart
6 Aug 24  i ii      `- Re: relearning C: why does an in-place change to a char* segfault?1David Brown
4 Aug 24  i i`- Re: relearning C: why does an in-place change to a char* segfault?1David Brown
4 Aug 24  i `- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
1 Aug 24  +- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
14 Aug 24  `- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch

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