Sujet : Re: A state transition diagram proves ...
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 18. Oct 2024, 04:47:59
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <veslpf$34ogr$1@dont-email.me>
References : 1 2 3 4
User-Agent : Mozilla Thunderbird
On 10/17/2024 10:27 PM, Richard Damon wrote:
On 10/17/24 9:47 PM, olcott wrote:
On 10/17/2024 8:13 PM, Richard Damon wrote:
On 10/17/24 7:31 PM, olcott wrote:
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
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When DDD is correctly emulated by HHH according
to the semantics of the x86 language DDD cannot
possibly reach its own machine address [00002183]
no matter what HHH does.
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+-->[00002172]-->[00002173]-->[00002175]-->[0000217a]--+
+------------------------------------------------------+
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That may not line up that same way when view
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https://en.wikipedia.org/wiki/State_diagram
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Except that 0000217a doesn't go to 00002172, but to 000015d2
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IS THIS OVER YOUR HEAD?
What is the first machine address of DDD that HHH
emulating itself emulating DDD would reach?
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Yes, HHH EMULATES the code at that address,
Which HHH emulates what code at which address?
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer
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