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On 05/02/2024 07:25 PM, Lawrence D'Oliveiro wrote:I read there's some C++ proposals to make for overloadingOn Thu, 2 May 2024 16:58:54 -0700, Chris M. Thomasson wrote:>
>The CPU can become a bottleneck.>
Then that becomes an entirely different situation from what we’re
discussing.
>So, there is no way to take advantage of multiple threads on Python?>
There is, but the current scheme has limitations in CPU-intensive
situations. They’re working on a fix, without turning it into a memory
hog
like Java.
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Yeah, it can be that way. "How are things?" "Yesterday
I implemented an entire web service on the cloud."
"Oh, really, how'd that go?" "I opened Initializer and
added a starter and copied how to pop the queue
and put the queue name in a file, then I added it
to git and it went into the CICD pipeline and now
it's in Prod." "Great." "It only even needs 1 gigabyte of RAM."
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Surely when it's like, "the only time this framework app
uses 1 gigabyte of RAM is at boot time it totally templates
itself into a gigabyte of RAM", then the guy's like "see,
I'm totally not using RAM." Yet it's like, "well, yeah,
but the meter for the RAM you're not using is on".
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At least then for re-routines, and if it helps it's quite
an idee fixe at this point, it's clear as described they can
be implemented in most languages with or without
threads as with just a minimum of threads and thread
locals and exception handling being well-defined and
the most usual sort of procedural call stack, then,
get this: taking plain usual code, giving it a ton of
threads, making every invocation one of these things,
and automatically parallelizing the code automatically
according to the flow-graph dependencies declared
in the synchronous, blocking, routine.
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Now _that's_ ridiculous.
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Though, in C++ with this sort of approach, the only
sort of "unusable" object is a future<result<T, E>>
as it were, or "the ubiquitous type" sort of thing
then as to overload its access as to invoke "get()",
if there was a sort of way to overload the "." and "->"
operators, and have them most simply be compiled
as invoke "." and "->". Does std::identity work this way?
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