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BGB <cr88192@gmail.com> writes:
>... in the 1D case, an array can be seen as functionally an
implicitly defined pointer ...
No, there is no implicitly defined pointer.
>
...
If you evaluate the expression `array_object` in most contexts, it's
implicitly converted to a pointer *value*, pointing to the 0th element
of the array object. There is still no implicit pointer object.
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