Re: question about nullptr

On 7/12/24 20:10, Scott Lurndal wrote:

Kaz Kylheku <643-408-1753@kylheku.com> writes:

On 2024-07-12, Scott Lurndal <scott@slp53.sl.home> wrote:

Kaz Kylheku <643-408-1753@kylheku.com> writes:

...

But, see, nobody in their right mind would say '\012` for that. '\0'
an octal escape sequence like '\012', not a role-based character
abstraction like '\n'.

 
Because '\012' is a character.   012 is an int.  Using the former
ensures that any overflow will be detected at compile time and

No, it does not. In C "An integer character constant has type int.".
(6.4.4.4p11), the same type as 012. A compiler could warn you about such
problems, but it's not required to, and a conforming compiler is not
allowed to reject code on that basis.