Re: relearning C: why does an in-place change to a char* segfault?

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Sujet : Re: relearning C: why does an in-place change to a char* segfault?
De : Keith.S.Thompson+u (at) *nospam* gmail.com (Keith Thompson)
Groupes : comp.lang.c
Date : 16. Aug 2024, 00:27:29
Autres entêtes
Organisation : None to speak of
Message-ID : <8734n5fjtq.fsf@nosuchdomain.example.com>
References : 1 2 3 4 5 6 7 8 9 10 11
User-Agent : Gnus/5.13 (Gnus v5.13)
Tim Rentsch <tr.17687@z991.linuxsc.com> writes:
Keith Thompson <Keith.S.Thompson+u@gmail.com> writes:
>
Tim Rentsch <tr.17687@z991.linuxsc.com> writes:
>
James Kuyper <jameskuyper@alumni.caltech.edu> writes:
>
Just as 1 is an integer literal whose value cannot be modified,
[...]
>
The C language doesn't have integer literals.  C has string
literals, and compound literals, and it has integer constants.
But C does not have integer literals.
>
Technically correct (but IMHO not really worth worrying about).
>
Anyone who flogs others posters for incorrectly using terminology
defined in the ISO C standard should set a good example by using
the ISO-C-defined terms correctly himself.

In fact I do.  In my own writing, I use the term "integer constant",
not "integer literal", when discussing C.  (It's likely I haven't
been 100% consistent.)

My point is that, while "integer literal" is inconsistent with the
terminology used in the C standard, it is not ambiguous or confusing.

C does not define the term "literal" (it defines the phrases "string
literal" and "compound literal").  The word "literal" by itself
is a very common term used when discussing programs in general.
When I looked into it last time this came up, I found that most of
the programming languages I looked into refer to 42 as a literal,
not as a constant.

I'll also note that the word "constant" is overloaded in C.
For example, as of C17, the description of "sizeof" says: "If the
type of the operand is a variable length array type, the operand
is evaluated; otherwise, the operand is not evaluated and the
result is an integer constant."  Though the meaning is clear,
it's an incorrect usage.  (C23 changes this to "... and the result
is an integer constant expression", which is better, but it's the
expression, not its result, that is an integer constant expression.)

Replacing the term "constant" by "literal" would, in my opinion,
improve the clarity of the standard.  I see no drawbacks to such
a change (other than the overhead of *any* change to the standard).

There is a proposal for C2y, authored by Jens Gustedt, to change the
term "constant" to "literal" for character, integer, and floating
constants.  (I think it's a good idea.)
>
<https://www.open-std.org/jtc1/sc22/wg14/www/docs/n3239.htm>
>
The more C is changed to resemble C++ the worse it becomes.  It
isn't surprising that you like it.

I presume that was intended as a personal insult.  I urge you to do
better.

I acknowledge your opinion.  I do not share it.

--
Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.com
void Void(void) { Void(); } /* The recursive call of the void */

Date Sujet#  Auteur
1 Aug 24 * relearning C: why does an in-place change to a char* segfault?105Mark Summerfield
1 Aug 24 +* Re: relearning C: why does an in-place change to a char* segfault?2Mark Summerfield
1 Aug 24 i`- Re: relearning C: why does an in-place change to a char* segfault?1Ben Bacarisse
1 Aug 24 +* Re: relearning C: why does an in-place change to a char* segfault?40Richard Harnden
1 Aug 24 i+- Re: relearning C: why does an in-place change to a char* segfault?1Mark Summerfield
1 Aug 24 i`* Re: relearning C: why does an in-place change to a char* segfault?38Bart
1 Aug 24 i `* Re: relearning C: why does an in-place change to a char* segfault?37Keith Thompson
1 Aug 24 i  +* Re: relearning C: why does an in-place change to a char* segfault?27Bart
1 Aug 24 i  i+- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
2 Aug 24 i  i+- Re: relearning C: why does an in-place change to a char* segfault?1James Kuyper
2 Aug 24 i  i+* Re: relearning C: why does an in-place change to a char* segfault?23Kaz Kylheku
2 Aug 24 i  ii`* Re: relearning C: why does an in-place change to a char* segfault?22Bart
2 Aug 24 i  ii +- Re: relearning C: why does an in-place change to a char* segfault?1Richard Damon
2 Aug 24 i  ii `* Re: relearning C: why does an in-place change to a char* segfault?20James Kuyper
2 Aug 24 i  ii  +- Re: relearning C: why does an in-place change to a char* segfault?1Bart
3 Aug 24 i  ii  +* Re: relearning C: why does an in-place change to a char* segfault?5Lawrence D'Oliveiro
3 Aug 24 i  ii  i`* Re: relearning C: why does an in-place change to a char* segfault?4Richard Damon
3 Aug 24 i  ii  i +- Re: relearning C: why does an in-place change to a char* segfault?1Joe Pfeiffer
4 Aug 24 i  ii  i +- Re: relearning C: why does an in-place change to a char* segfault?1Lawrence D'Oliveiro
12 Aug 24 i  ii  i `- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
14 Aug 24 i  ii  `* Re: relearning C: why does an in-place change to a char* segfault?13Tim Rentsch
14 Aug 24 i  ii   +* Re: relearning C: why does an in-place change to a char* segfault?10Keith Thompson
16 Aug 24 i  ii   i`* Re: relearning C: why does an in-place change to a char* segfault?9Tim Rentsch
16 Aug 24 i  ii   i `* Re: relearning C: why does an in-place change to a char* segfault?8Keith Thompson
28 Sep 24 i  ii   i  `* Re: relearning C: why does an in-place change to a char* segfault?7Tim Rentsch
28 Sep 24 i  ii   i   `* Re: relearning C: why does an in-place change to a char* segfault?6Keith Thompson
28 Sep 24 i  ii   i    `* Re: relearning C: why does an in-place change to a char* segfault?5Janis Papanagnou
28 Sep 24 i  ii   i     `* Re: relearning C: why does an in-place change to a char* segfault?4Phillip Frabott
28 Sep 24 i  ii   i      `* Re: relearning C: why does an in-place change to a char* segfault?3Keith Thompson
29 Sep 24 i  ii   i       `* Re: relearning C: why does an in-place change to a char* segfault?2Phillip Frabott
29 Sep 24 i  ii   i        `- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
14 Aug 24 i  ii   `* Re: relearning C: why does an in-place change to a char* segfault?2James Kuyper
16 Aug 24 i  ii    `- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
4 Aug 24 i  i`- Re: relearning C: why does an in-place change to a char* segfault?1Bonita Montero
12 Aug 24 i  `* Re: relearning C: why does an in-place change to a char* segfault?9Tim Rentsch
13 Aug 24 i   `* Re: relearning C: why does an in-place change to a char* segfault?8Vir Campestris
13 Aug 24 i    +* Re: relearning C: why does an in-place change to a char* segfault?3Keith Thompson
14 Aug 24 i    i+- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
14 Aug 24 i    i`- Re: relearning C: why does an in-place change to a char* segfault?1David Brown
14 Aug 24 i    `* Re: relearning C: why does an in-place change to a char* segfault?4Tim Rentsch
14 Aug 24 i     `* Re: relearning C: why does an in-place change to a char* segfault?3Keith Thompson
14 Aug 24 i      `* Re: relearning C: why does an in-place change to a char* segfault?2Kaz Kylheku
14 Aug 24 i       `- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
1 Aug 24 +* No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?38Michael S
1 Aug 24 i`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?37David Brown
2 Aug 24 i `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?36candycanearter07
2 Aug 24 i  +* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?34Keith Thompson
2 Aug 24 i  i+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?28Richard Harnden
2 Aug 24 i  ii+- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1James Kuyper
2 Aug 24 i  ii+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?24Keith Thompson
2 Aug 24 i  iii+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?5Richard Damon
2 Aug 24 i  iiii+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?3James Kuyper
2 Aug 24 i  iiiii`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2Richard Damon
12 Aug 24 i  iiiii `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
12 Aug 24 i  iiii`- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
2 Aug 24 i  iii+* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?15Chris M. Thomasson
3 Aug 24 i  iiii`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?14Ben Bacarisse
3 Aug 24 i  iiii `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?13Chris M. Thomasson
5 Aug 24 i  iiii  `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?12Ben Bacarisse
5 Aug 24 i  iiii   `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?11Chris M. Thomasson
5 Aug 24 i  iiii    +- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Chris M. Thomasson
5 Aug 24 i  iiii    `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?9Ben Bacarisse
5 Aug 24 i  iiii     `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?8Chris M. Thomasson
5 Aug 24 i  iiii      `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?7Ben Bacarisse
6 Aug 24 i  iiii       +* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?5Chris M. Thomasson
6 Aug 24 i  iiii       i`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?4Ben Bacarisse
6 Aug 24 i  iiii       i `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?3Chris M. Thomasson
7 Aug 24 i  iiii       i  `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2Ben Bacarisse
13 Aug 24 i  iiii       i   `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Chris M. Thomasson
6 Aug 24 i  iiii       `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Chris M. Thomasson
12 Aug 24 i  iii`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?3Tim Rentsch
12 Aug 24 i  iii `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2Keith Thompson
3 Sep 24 i  iii  `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
25 Aug 24 i  ii`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2dave thompson 2
25 Aug 24 i  ii `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
12 Aug 24 i  i`* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?5Tim Rentsch
12 Aug 24 i  i `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?4Keith Thompson
13 Aug 24 i  i  `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?3Tim Rentsch
13 Aug 24 i  i   `* Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?2David Brown
13 Aug 24 i  i    `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
3 Aug 24 i  `- Re: No warning at implicit removal of const. Was: relearning C: why does an in-place change to a char* segfault?1David Brown
1 Aug 24 +- Re: relearning C: why does an in-place change to a char* segfault?1James Kuyper
1 Aug 24 `* Re: relearning C: why does an in-place change to a char* segfault?23Kaz Kylheku
1 Aug 24  +* Re: relearning C: why does an in-place change to a char* segfault?20Bart
1 Aug 24  i+- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
1 Aug 24  i+- Re: relearning C: why does an in-place change to a char* segfault?1Ben Bacarisse
2 Aug 24  i+* Re: relearning C: why does an in-place change to a char* segfault?3Kaz Kylheku
2 Aug 24  ii+- Re: relearning C: why does an in-place change to a char* segfault?1Bart
12 Aug 24  ii`- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
3 Aug 24  i`* Re: relearning C: why does an in-place change to a char* segfault?14David Brown
4 Aug 24  i +* Re: relearning C: why does an in-place change to a char* segfault?12Keith Thompson
4 Aug 24  i i+* Re: relearning C: why does an in-place change to a char* segfault?10Lawrence D'Oliveiro
4 Aug 24  i ii`* Re: relearning C: why does an in-place change to a char* segfault?9Keith Thompson
4 Aug 24  i ii +* Re: relearning C: why does an in-place change to a char* segfault?2Richard Damon
12 Aug 24  i ii i`- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch
5 Aug 24  i ii `* Re: relearning C: why does an in-place change to a char* segfault?6Lawrence D'Oliveiro
5 Aug 24  i ii  `* Re: relearning C: why does an in-place change to a char* segfault?5Keith Thompson
5 Aug 24  i ii   `* Re: relearning C: why does an in-place change to a char* segfault?4Lawrence D'Oliveiro
6 Aug 24  i ii    `* Re: relearning C: why does an in-place change to a char* segfault?3Keith Thompson
6 Aug 24  i ii     `* Re: relearning C: why does an in-place change to a char* segfault?2Bart
6 Aug 24  i ii      `- Re: relearning C: why does an in-place change to a char* segfault?1David Brown
4 Aug 24  i i`- Re: relearning C: why does an in-place change to a char* segfault?1David Brown
4 Aug 24  i `- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
1 Aug 24  +- Re: relearning C: why does an in-place change to a char* segfault?1Keith Thompson
14 Aug 24  `- Re: relearning C: why does an in-place change to a char* segfault?1Tim Rentsch

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