Re: how to make it work

fir <fir@grunge.pl> writes:

see such code
>
>
long long unsigned tag ;
>
void foo(long long unsigned tag)
{
 if(tag=='warsaw') printf("\nwarsaw");
 if(tag=='paris')  printf("\nparis");
 if(tag=='new york') printf("\nnew york");
 if(tag=='old york') printf("\nold york");
 if(tag=='very old york') printf("\nvery old york");
>
>
}
>
int main(void)
{
 foo('warsaw');
 foo('paris');
 foo('new york');
 foo('old york');
 foo('very old york');
>
 return 'bye';
}
>
and maybe guess the result (or how it should be)
(later i may tell you)
>
the problem is how to make it work i want to use that kind of
'tags' and would like to use it assuming at least 8 characters
work okay i mean the code above would "catch" only on proper tag and
each one would be printed one time
>
right now it dont - is thsi a way to make it work
(maybe except the last one as i understand
 if(tag=='old york') printf("\nold york");
 if(tag=='very old york') printf("\nvery old york");
may be treated as the same
>
(i need it to work on 32 bit old mingw/gcc)

That's unfortunate because this can be done in a portable and relatively
convenient way in modern C:

#include <stdint.h>
#include <stdio.h>

typedef union {
     unsigned char bytes[sizeof (uint64_t)];
     uint64_t tag;
} Tag;

void foo(Tag t)
{
     if (t.tag == (Tag){"warsaw"}.tag)
          printf("warsaw\n");
}

int main(void)
{
     foo((Tag){"warsaw"});
}

With a little bit more work, you can get this to work in older C without
compound literals.

But depending on what your ultimate goal is, you might want to look at
how Lisp implementations "intern" their symbols.  That can avoid the
obvious length limitations while making for very efficient equality
comparisons.

--
Ben.