Re: constexpr keyword is unnecessary

Em 10/13/2024 8:49 AM, Bonita Montero escreveu:

Am 13.10.2024 um 13:37 schrieb Thiago Adams:
 

Yes.
constexpr is like - "require the initializer to be a constant expression." But the compiler will have to check it anyway.

 I cannot understand why you are so militantly against this
new language feature that can be understood in 10 seconds.
 

I have seen code like this:
void func()
{
    constexpr int c = 1;
    f(c);
}
For some reason, people believe that adding constexpr will magically improve optimization. In reality, it doesn't change anything compared to const and often reflects a misunderstanding of how the compiler works. As a result, I end up having to explain it. In this sense, constexpr is viral and spreads confusion.