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On 14/10/2024 23:17, Chris M. Thomasson wrote:So, any similar to:On 10/13/2024 7:57 PM, olcott wrote:Similar, but different because HHH only performs a /partial/ step by step emulation of DDD - it stops emulating after a while and returns, so DDD() halts. foobar() will never halt (ignoring physical resource constraints like running out of stack). foobar() undergoes infinite recursive call. DDD() exhibits /finite/ recursive emulation, then halts.On 10/13/2024 11:34 AM, Kaz Kylheku wrote:[...]On 2024-10-12, Chris M. Thomasson <chris.m.thomasson.1@gmail.com> wrote:>On 10/12/2024 11:28 AM, Janis Papanagnou wrote:>On 12.10.2024 11:32, Jan van den Broek wrote:>2024-10-12, Chris M. Thomasson <chris.m.thomasson.1@gmail.com> schrieb:>On 10/11/2024 7:50 PM, olcott wrote:>
[Schnipp]
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As I see it, the main Halting Problem is Olcott not halting.
LOL! - A very nice one. Thanks for that. :-)
I second that. :^)
You're likely thousand-seconding that. The Olcott not halting joke
is many years old now, and will likely come up again.
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My cancer has gotten worse.
>
*ChatGPT explains why rebuttals of my work are incorrect*
https://chatgpt.com/share/6709e046-4794-8011-98b7-27066fb49f3e
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I had to dumb this down from the original halting problem
input so that reviewers can verify that HHH is correct
without hardly paying any attention at all:
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void DDD()
{
HHH(DDD);
return;
}
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When HHH is an x86 emulation based termination analyzer
then each DDD emulated by any HHH that it calls never returns.
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Isn't that similar to:
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void foobar()
{
foobar();
}
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? >
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