Re: constexpr keyword is unnecessary

On 29/10/2024 09:16, Thiago Adams wrote:
Edit to fix the sample
// Here we acknowledge the truncation
void f(int i) {
     ...
     const unsigned char c = i; [[!truncation]];
}
// Warning: there is no truncation to acknowledge.
void f(unsigned char i) {
     ...
     const unsigned char c = i; [[!truncation]];
}