Re: else ladders practice

On 16.11.2024 16:14, James Kuyper wrote:

On 11/16/24 04:42, Stefan Ram wrote:
...

[...]
>
#include <stdio.h>
>
const char * english( int const n )
{ const char * result;
  if( n == 0 )result = "zero";
  if( n == 1 )result = "one";
  if( n == 2 )result = "two";
  if( n == 3 )result = "three";
  else        result = "four";
  return result; }

That's indeed a nice example. Where you get fooled by treachery
"trustiness" of formatting[*]. - In syntax we trust! [**]

>
void print_english( int const n )
{ printf( "%s\n", english( n )); }
>
int main( void )
{ print_english( 0 );
  print_english( 1 );
  print_english( 2 );
  print_english( 3 );
  print_english( 4 ); }

 
Nice. It did take a little while for me to figure out what was wrong,
but since I knew that something was wrong, I did eventually find it -
without first running the program.

Same here. :-)

Janis

[*] Why do I have to think of Python now? - Never mind. Better
let sleeping dogs lie.

[**] As far as I am concerned.