Re: "A diagram of C23 basic types"

On 08/04/2025 20:14, James Kuyper wrote:

On 4/8/25 04:39, David Brown wrote:

On 07/04/2025 20:35, James Kuyper wrote:

On 4/3/25 18:00, Waldek Hebisch wrote:

Tim Rentsch <tr.17687@z991.linuxsc.com> wrote:

...

Not always practical.  A good example is the type size_t.  If a
function takes an argument of type size_t, then the symbol size_t
should be defined, no matter which header the function is being
declared in.

>
Why?  One can use a type without a name for such type.

>
How would you declare a pointer to a function type such that it is
compatible with such a function's type?

>
The C23 "typeof" operator lets you work with the type of a value or
expression.  So you first have an object or value of type "size_t",
that's all you need.  Unfortunately, there are no convenient literal
suffixes that could be used here.

 I can see how that would work with the return type of a function, but
how would it apply to an argument of a function?
 

Something like :
memcpy(p, q, (typeof(sizeof(int))) 100);
I haven't tested that on a C23 compiler, because I really don't think it is the kind of thing I'd write in real code!