Sujet : Re: Is there a way in Fortran to designate an integer value as integer*8 ?
De : sgk (at) *nospam* REMOVEtroutmask.apl.washington.edu (Steven G. Kargl)
Groupes : comp.lang.fortranDate : 03. Oct 2024, 16:07:41
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vdmbvt$3p2dv$2@dont-email.me>
References : 1 2
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On Thu, 03 Oct 2024 14:45:31 +0200, R Daneel Olivaw wrote:
Lynn McGuire wrote:
I need many of my integers to be integer*8 in my port to 64 bit. In
C/C++ code, I can say 123456L to mean a long long value, generally 64
bit. Is there a corresponding way to do this in Fortran or am I stuck
with:
call xyz (1)
subroutine xyz (ivalue)
integer*8 ivalue
...
return end
must be:
integer*8 ivalue
...
ivalue = 1
call xyz (ivalue)
This is not actually a Fortran issue as such, it's all about a specific
compiler (GNU Fortran).
If we overlook the nonstandard type in the declaration, and agree
that the compiler will accept 'integer*8', then the program is
still invalid Fortran. It's technically not a Fortran issue. It
is a programmer issue.
-- steve