Re: Is there a way in Fortran to designate an integer value as integer*8 ?

On Thu, 03 Oct 2024 22:28:31 +0100, Clive Page wrote:

On 03/10/2024 20:59, Steven G. Kargl wrote:

My personal recommendation would be to do a proper porting from
integer (aka integer*4) to integer(kind=8).  And, yes, 8 in the
'kind=8' is not portable.
 

 
Yes because different compilers use different integer kind numbers for

different purposes: at least one uses kinds 1, 2, 3, 4 for the four most
common numbers of bytes where other compilers use 1, 2, 4, 8.   But if you
use integer(kind=int64) this is portable.

(Although unlikely) what happens when int64 = -1?
I suppose 'integer(-1)' is portable to the extent
that a compiler will error out.

--
steve