Re: A missing iterator on itertools module?

ast <none@none.fr> wrote or quoted:

s1 = "AZERTY"
s2 = "QSDFGH"
s3 = "WXCVBN"
and I need an itertor who delivers
A Q W Z S C E D C ...
I didn't found anything in itertools to do the job.
So I came up with this solution:
list(chain.from_iterable(zip("AZERTY", "QSDFGH", "WXCVBN")))

    Maybe you meant "zip(s1,s2,s3)" as the definition of s1, s2,
   and s3 otherwise would not be required. Also the "list" is not
   necessary because "chain.from_iterable" already is an iterable.
   You could also use "*" instead of "list" to print it. So,
 import itertools as _itertools
s =[ "AZERTY", "QSDFGH", "WXCVBN" ]
print( *_itertools.chain.from_iterable( zip( *s )))
    . But these are only minor nitpicks; you have found a nice solution!