Re: diff1(x) in Python: True if all adjacent items differ by 1, False otherwise.

On 6/15/2024 5:13 PM, HenHanna wrote:

On 6/15/2024 2:30 PM, Paul Rubin wrote:

HenHanna <HenHanna@devnull.tb> writes:

def diff1(x):
     if len(x) <= 1: return True
     for i in range(len(x) - 1):
         if abs(x[i] - x[i+1]) != 1:    return False
     return True

>
def diff2(x):
   return all(abs(a-b)==1) for a,b in zip(x,x[1:]))

  Does this work when x is  []  or  [1]  ?

i'm pretty sure that  x[1:]  would  raise an error.
             Lispers can learn from Pythonicity and vice versa.