Sujet : Re: diff1(x) in Python: True if all adjacent items differ by 1, False otherwise.
De : michael.stemper (at) *nospam* gmail.com (Michael F. Stemper)
Groupes : comp.lang.python comp.lang.lispDate : 17. Jun 2024, 14:11:23
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v4pclr$luk9$1@dont-email.me>
References : 1 2 3
User-Agent : Mozilla/5.0 (X11; Linux x86_64; rv:102.0) Gecko/20100101 Thunderbird/102.11.0
On 15/06/2024 19.13, HenHanna wrote:
On 6/15/2024 2:30 PM, Paul Rubin wrote:
HenHanna <HenHanna@devnull.tb> writes:
def diff1(x):
if len(x) <= 1: return True
for i in range(len(x) - 1):
if abs(x[i] - x[i+1]) != 1: return False
return True
>
def diff2(x):
return all(abs(a-b)==1) for a,b in zip(x,x[1:]))
Does this work when x is [] or [1] ?
The easiest way to find out would be to type it in to REPL and
give it a whirl.
-- Michael F. Stemper87.3% of all statistics are made up by the person giving them.
diff1(x) in Python: True if all adjacent items differ by 1, False otherwise.
Re: diff1(x) in Python: True if all adjacent items differ by 1, False otherwise.