Re: Using 'with open(...) as ...' together with configparser.ConfigParser.read

Jon Ribbens <jon+usenet@unequivocal.eu> writes:

On 2024-10-30, Loris Bennett <loris.bennett@fu-berlin.de> wrote:

Jon Ribbens <jon+usenet@unequivocal.eu> writes:

As per the docs you link to, the read() method only takes filename(s)
as arguments, if you have an already-open file you want to read then
you should use the read_file() method instead.

>
As you and others have pointed out, this is indeed covered in the docs,
so mea culpa.
>
However, whereas I can see why you might want to read the config from a
dict or a string, what would be a use case in which I would want to
read from an open file rather than just reading from a file(name)?

>
The ConfigParser module provides read(), read_file(), read_string(),
and read_dict() methods. I think they were just trying to be
comprehensive. It's a bit non-Pythonic really.

OK, but is there a common situation might I be obliged to use
'read_file'?  I.e. is there some common case where the file name is not
available, only a corresponding file-like object or stream?

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