(hijk is a Subseq of Hijack) (abcde is a Subseq of Absconded)

Liste des GroupesRevenir à cl python 
Sujet : (hijk is a Subseq of Hijack) (abcde is a Subseq of Absconded)
De : HenHanna (at) *nospam* dev.null (HenHanna)
Groupes : rec.puzzles comp.lang.lisp comp.lang.python
Date : 16. Feb 2025, 19:54:38
Autres entêtes
Organisation : novaBBS
Message-ID : <3375c051ba0285b18865c4799b391d36@www.novabbs.com>
User-Agent : Rocksolid Light
Does this  come standard in a library (package) in Python or
(Gauche)Scheme?
________________
def Subseq(X, Y):
    i,j = 0,0
    while i < len(X) and j < len(Y):
        if X[i] == Y[j]:   i += 1
        j += 1
    return i == len(X)
___________________   (abcde   is a Subseq of  Absconded)
___________________   (hijk    is a Subseq of  Hijack)

Date Sujet#  Auteur
16 Feb 25 o (hijk is a Subseq of Hijack) (abcde is a Subseq of Absconded)1HenHanna

Haut de la page

Les messages affichés proviennent d'usenet.

NewsPortal