Sujet : Re: Parsing namespace name strings
De : emiliano (at) *nospam* example.invalid (Emiliano)
Groupes : comp.lang.tclDate : 30. Nov 2024, 00:16:01
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <20241129201601.dde7fad0c89a3239a0ae6b8a@example.invalid>
References : 1
User-Agent : Sylpheed 3.5.1 (GTK+ 2.24.32; i686-pc-linux-gnu)
On Fri, 29 Nov 2024 21:03:25 +0000
Alan Grunwald <
nospam.nurdglaw@gmail.com> wrote:
I find I regularly want to know things like "what is first part of a
namespace name", "the first two parts" etc. I generally want to get the
same answer whether the name is a::b::c or ::a::b::c.
I can (and do) do this by getting a list of parts via something like
split [string map {"::" ":"} $name] ":"
but this is clunky - is there something like [namespace split] that
would return a list of parts?
For example, I'd like namespace split a::b::c to return {a b c}, and
namespace split ::d::e::f::g to return {d e f g}.
Easy combining [namespace tail] and [namespace qualifiers]:
proc ns2list {ns} {
set l {}
while {$ns ne {}} {
lappend l [namespace tail $ns]
set ns [namespace qualifiers $ns]
}
lreverse $l
}
% ns2list foo::bar::
foo bar {}
% ns2list foo::bar
foo bar
% ns2list ::::foo::bar::
foo bar {}
% ns2list ::foo::bar
foo bar
% ns2list {}
%
As a followup, if I write a proc namespaceSplit that does what I want,
is there a user-level way to modify the [namespace] command so that a
can execute namespaceSplit via [namespace split]?
Since the [namespace] command is an ensemble, its easy to add a subcommand
% namespace ensemble configure namespace -map [dict merge [namespace ensemble configure namespace -map] {split ::ns2list}]
% namespace split ::foo::bar::baz
foo bar baz
Many thanks
Regards
-- Emiliano