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On 2/27/2025 3:00 PM, joes wrote:You didn't ask for the trace of HHH.Am Thu, 27 Feb 2025 13:06:41 -0600 schrieb olcott:On 2/27/2025 3:36 AM, Fred. Zwarts wrote:Look at what HHH1 does.Op 27.feb.2025 om 05:40 schreef olcott:That dishonestly dodged the original question:On 2/26/2025 9:52 AM, joes wrote:HHH1 did a correct simulation, so, there it is.Am Wed, 26 Feb 2025 08:49:42 -0600 schrieb olcott:If I am wrong then a correct simulation must exist.On 2/26/2025 3:48 AM, Fred. Zwarts wrote:There can be no correct continuation.Op 26.feb.2025 om 05:50 schreef olcott:>On 2/25/2025 10:21 PM, Richard Damon wrote:What are the correct first 15 lines of DD emulated by HHH.You already know that you are stupidly wrong about the emulationThe error in the simulation occurs already at the 5th
being incorrect or you would have provided the correct emulation
sequence long ago.
What are the first 15 lines of DD correctly emulated by HHH?
instruction,
the 'call 000015c3'. Instead of simulating this instruction,
What are the first 15 *lines of DD* correctly emulated by HHH?
_DD()
[00002133] 55 push ebp ; housekeeping [00002134] 8bec
mov ebp,esp ; housekeeping [00002136] 51 push ecx ;
make space for local [00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404 add esp,+04 [00002144] 8945fc mov
[ebp-04],eax [00002147] 837dfc00 cmp dword [ebp-04],+00 [0000214b]
7402 jz 0000214f [0000214d] ebfe jmp 0000214d [0000214f]
8b45fc mov eax,[ebp-04]
[00002152] 8be5 mov esp,ebp [00002154] 5d pop ebp
[00002155] c3 ret Size in bytes:(0035) [00002155]Anyway: ignoring the call to HHHIt moronically stupid unless HHH ignores this call and HHH does not
ignore this call.
What are the hexadecimal machine addresses of the first 10 lines of DDOr lazy.
correctly emulated by HHH?
A failure to answer that question with ten hexadecimal values proves
that the reviewer is either dishonest or clueless.
--because it doesn't call DD in turn,
we continue with 2141 until the conditional jump, whereupon we either
enter an infinite loop (which is more than 15 instructions)
or proceed to return (which is 13 instructions), depending on the
return value of HHH.
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