Re: How could HHH report on the behavior of its caller?

On 5/14/25 9:30 PM, olcott wrote:

void DDD()
{
   HHH(DDD);
   return;
}
 int main()
{
   DDD();
}
 If HHH cannot report on the behavior of its caller
because this is a ridiculous requirement then how
can HHH report on the direct execution of DDD()
(AKA its caller).
 

Because it is given the code of DDD, and thus doesn't need to know about "It caller"
I guess you are just admitting your stupidity.