Sujet : Re: DDD correctly emulated by HHH is Correctly rejected as non-halting V2
De : noreply (at) *nospam* example.org (joes)
Groupes : comp.theoryDate : 16. Jul 2024, 19:06:57
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <fde630817c49562bc765bdbc98e16a1582bcad53@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
User-Agent : Pan/0.145 (Duplicitous mercenary valetism; d7e168a git.gnome.org/pan2)
Am Tue, 16 Jul 2024 08:54:10 -0500 schrieb olcott:
On 7/16/2024 3:23 AM, joes wrote:
Am Mon, 15 Jul 2024 16:03:30 -0500 schrieb olcott:
On 7/15/2024 3:58 PM, joes wrote:
Am Mon, 15 Jul 2024 10:52:34 -0500 schrieb olcott:
On 7/15/2024 9:04 AM, joes wrote:
Am Mon, 15 Jul 2024 07:23:57 -0500 schrieb olcott:
On 7/15/2024 3:59 AM, joes wrote:
Am Sun, 14 Jul 2024 22:35:03 -0500 schrieb olcott:
On 7/14/2024 10:02 PM, Mike Terry wrote:
>
Any input that must be aborted to prevent the non termination of
simulating termination analyzer HHH necessarily specifies
non-halting behavior or it would never need to be aborted.
It's just that the input HHH halts and does not need to be
aborted.
At the point that it is aborted it did need to be aborted
Because it hadn't halted yet?
Because HHH has seen a repeating state that proves that DDD
correctly emulated by HHH cannot possibly ever stop running unless
aborted.
Which state is it that repeats forever?
*It had never been which state DOES repeat forever*
*It has always been which state WOULD repeat forever if not aborted*
Well then, which state of HHH would repeat forever?
It is not "which state of HHH would repeat forever?"
It is: Which state of HHH would repeat forever if not aborted?
Those two are the same, but different to what you said above.
HHH does not repeat forever because it makes sure to stop simulating
anything that does.
Infinite_Loop() doesn't even repeat forever because it is aborted.
By itself it does.
-- Am Fri, 28 Jun 2024 16:52:17 -0500 schrieb olcott:Objectively I am a genius.
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