Sujet : Re: Can D simulated by H terminate normally?
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 29. Apr 2024, 16:56:03
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v0oce3$1q3aq$4@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14
User-Agent : Mozilla Thunderbird
On 4/29/2024 9:37 AM, Alan Mackenzie wrote:
[ Followup-To: set. ]
In comp.theory olcott <polcott333@gmail.com> wrote:
On 4/28/2024 1:39 PM, Richard Damon wrote:
On 4/28/24 2:19 PM, olcott wrote:
[ .... ]
Even the term "halting" is problematic.
For 15 years I thought it means stops running for any reason.
And that shows your STUPIDITY, not an error in the Theory.
Now I know that it means reaches the final state.
There can be several distinct final states in a turing machine. Do you
mean, perhaps, "it means reaches _A_ final state"?
Sure.
Half the people here may not know that.
No, I suspect most of the people here are smarter than that.
Having been aborted (if such were possible) is merely another final state
for a TM.
No it definitely is not.
When the payroll system crashes 10% of the way through calculating
payroll we cannot say that everyone has been paid.
Yet again only rhetoric with no actual reasoning.
Do you believe:
(a) Halting means stopping for any reason.
(b) Halting means reaching a final state.
(a) and (b) are identical. A TM having stopped means it has reached a
final state, and vice versa.
No that is incorrect.
In software engineering terms halting means reaching a final
state and terminating normally.
(c) Neither.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer