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Op 02.jun.2024 om 20:37 schreef olcott:HH(DD,DD) correctly simulates DD(DD) that calls HH(DD,DD) in recursiveOn 6/2/2024 1:16 PM, Fred. Zwarts wrote:Similarly HH(DD,DD) correctly detects that HH correctly simulated by HH cannot possibly halt, because HH keeps calling HH(DD,DD) in recursiveOp 02.jun.2024 om 16:58 schreef olcott:>On 6/2/2024 4:36 AM, joes wrote:>Am Sat, 01 Jun 2024 17:37:28 -0500 schrieb olcott:>
>On 6/1/2024 5:30 PM, Richard Damon wrote:>On 6/1/24 5:27 PM, olcott wrote:On 6/1/2024 4:15 PM, Richard Damon wrote:On 6/1/24 4:35 PM, olcott wrote:On 6/1/2024 3:29 PM, Richard Damon wrote:On 6/1/24 12:46 PM, olcott wrote:On 6/1/2024 11:33 AM, Richard Damon wrote:On 6/1/24 12:18 PM, olcott wrote:On 6/1/2024 11:08 AM, Richard Damon wrote:On 6/1/24 11:58 AM, olcott wrote:On 6/1/2024 10:46 AM, Richard Damon wrote:On 6/1/24 10:00 AM, olcott wrote:Not simulating an infinite number of steps of infinite recursion is>Every DD correctly simulated by any HH of the infinite set of HH/DD>
pairs that match the above template never reaches past its own
simulated line 03 in 1 to ∞ steps of correct simulation of DD by HH.
But since the simulation was aborted,
*The above never mentions anything about any simulation being aborted*
incorrect. You always forget this requirement: the simulation must be
complete.
When every possible simulation where DD is correctly simulated by HH
never reaches past its own simulated line 03 then we know for sure that
No DD correctly simulated by HH ever halts.
Similarly:
>
When every possible simulation where HH is correctly simulated by itself
never reaches its own return then we know for sure that no HH correctly simulated by HH ever halts.
>
*I am not going to keep repeating myself, I will simply give up on you*
>
HH(DD,DD) correctly detects that DD correctly simulated by HH cannot
possibly halt because HH keeps calling HH(DD,DD) in recursive
simulation.
simulation.
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