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Am Wed, 03 Jul 2024 09:45:57 -0500 schrieb olcott:By definition DDD calls it simulator.On 7/3/2024 9:39 AM, joes wrote:I repeat.Am Wed, 03 Jul 2024 08:21:40 -0500 schrieb olcott:On 7/3/2024 3:26 AM, Fred. Zwarts wrote:Which semantics?Op 02.jul.2024 om 21:48 schreef olcott:On 7/2/2024 2:22 PM, Fred. Zwarts wrote:Op 02.jul.2024 om 20:43 schreef olcott:On 7/2/2024 1:59 AM, Mikko wrote:On 2024-07-01 12:44:57 +0000, olcott said:On 7/1/2024 1:05 AM, Mikko wrote:On 2024-06-30 17:18:09 +0000, olcott said:>
Richard just said that he affirms that when DDD correctly
simulated by HHH calls HHH(DDD) that this call returns even
though the semantics of the x86 language disagrees.
HHH halts by definition. Why can’t DDD?As long as it is impossible for DDD correctly emulated by HHH to reachDDD correctly emulated by HHH calls an emulated HHH(DDD) that emulatesBut HHH aborts, so the cycle does end.
DDD that calls an emulated HHH(DDD)
in a cycle that cannot end unless aborted.
its own ret instruction then DDD never halts even when its stops running
because its emulation was aborted.
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