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On 7/15/2024 3:37 AM, Mikko wrote:That you agree does not mean that it is wrong.On 2024-07-15 03:41:24 +0000, olcott said:No that is wrong. The finite string must encode a Turing machine.
On 7/14/2024 9:04 PM, Richard Damon wrote:That's right. But the finite string can be a description of a Turing machine.On 7/14/24 9:27 PM, olcott wrote:Turing machines only operate on finite strings they doAny input that must be aborted to prevent the non terminationExcpet, as I have shown, it doesn't.
of simulating termination analyzer HHH necessarily specifies
non-halting behavior or it would never need to be aborted.
Your problem is you keep on ILEGALLY changing the input in your argument because you have misdefined what the input is.
The input to HHH is ALL of the memory that it would be accessed in a correct simulation of DDD, which includes all the codd of HHH, and thus, if you change HHH you get a different input.
If you want to try to claim the input is just the bytes of the function DDD proper then you are just admitting that you are nothing more than a lying idiot that doesn't understand the problem,
not operate on other Turing machines *dumbo*
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