Sujet : Re: Any honest person that knows the x86 language can see... predict correctly
De : F.Zwarts (at) *nospam* HetNet.nl (Fred. Zwarts)
Groupes : comp.theoryDate : 01. Aug 2024, 08:46:53
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v8fehe$22ege$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13
User-Agent : Mozilla Thunderbird
Op 01.aug.2024 om 05:51 schreef olcott:
On 7/31/2024 10:08 PM, wij wrote:
On Tue, 2024-07-30 at 18:50 -0500, olcott wrote:
>
It is not supposed to be a general solution to the halting problem.
it only shows how the "impossible" input is correctly determined
to be non halting.
>
>
But how do you determine it is non-halting?
>
As I know you are even unable to define what 'halt' mean !!!
>
I have done this thousands of times and after someone
has read these thousands of times they say that I never
said it once.
void DDD()
{
HHH(DDD);
return;
}
int main()
{
HHH(DDD);
}
If DDD correctly emulated by HHH cannot possibly
reach its return instruction then it never halts.
But a correct simulation is impossible. HHH cannot possibly simulate itself correctly.
So you made the same error thousands of times.
You never showed a correct definition.