Sujet : Re: Anyone that claims this is not telling the truth --- V4
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 19. Aug 2024, 13:34:54
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v9ve5e$2rjt1$6@dont-email.me>
References : 1 2 3 4 5 6 7 8
User-Agent : Mozilla Thunderbird
On 8/19/2024 2:26 AM, Mikko wrote:
On 2024-08-18 12:48:32 +0000, olcott said:
>
x86utm takes the compiled Halt7.obj file of this c program
https://github.com/plolcott/x86utm/blob/master/Halt7.c
Thus making all of the code of HHH directly available to
DDD and itself. HHH emulates itself emulating DDD.
It is not an emulation of DDD if the execution differs from a
real execution of DDD.
*Everything that is not expressly stated below is*
*specified as unspecified*
void DDD()
{
HHH(DDD);
return;
}
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
*It is a basic fact that DDD emulated by HHH according to*
*the semantics of the x86 language cannot possibly stop*
*running unless aborted* (out of memory error excluded)
X = DDD emulated by HHH∞ according to the semantics of the x86 language
Y = HHH∞ never aborts its emulation of DDD
Z = DDD never stops running
My claim boils down to this: (X ∧ Y) ↔ Z
void EEE()
{
HERE: goto HERE;
}
HHHn correctly predicts the behavior of DDD the same
way that HHHn correctly predicts the behavior of EEE.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer