Re: HHH(DDD) computes the mapping from its input to HHH emulating itself emulating DDD

On 12/4/24 8:06 PM, olcott wrote:

On 12/4/2024 6:11 PM, Richard Damon wrote:

On 12/4/24 9:27 AM, olcott wrote:

On 12/3/2024 5:39 PM, Richard Damon wrote:

On 12/3/24 6:08 PM, olcott wrote:

On 12/3/2024 3:03 AM, joes wrote:

Am Mon, 02 Dec 2024 20:48:49 -0600 schrieb olcott:

On 11/28/2024 1:48 PM, joes wrote:

>

You said:
  >>> HHH can't simulate itself.
That is WRONG !!!
HHH DOES EMULATE ITSELF PROVING THAT IT CAN EMULATE ITSELF.

We know that HHH halts. It doesn't simulate itself halting.
>

>
Please try and explain how you are not dishonest what you
try to change the subject from my rebuttal of your statement:
>
 >>> HHH can't simulate itself.
>
That HHH does emulate itself emulating DDD proves
THAT IT CAN DO THIS.
>

>
But only if your think that wrong answer can be right.

>
I did not mention anything about answers my entire
scope is that HHH does emulate itself emulating DDD
thus conclusively proving that HHH can emulated itself
emulating DDD.
>
Whenever you go out-of-scope like this it surely
seems dishonest to me.
>

>
But the behaivor that HHH shows that it has *IS* an "answer",

>
DDD emulated by any HHH according to the semantics of
the x86 language cannot possibly reach its "ret" instruction
whether HHH aborts this emulation after N steps or never aborts.
>
>

 Just a nonsense sentence, since HHH can't emulate HHH as it isn't given it,